Step 1: Range equation for projectile.
The range \( R \) of a projectile launched with velocity \( v \) at an angle \( \theta \) is given by:
\[
R = \frac{v^2 \sin(2\theta)}{g}
\]
where \( g \) is the acceleration due to gravity.
Step 2: Compare ranges at different angles.
At 15°, the range is 1.5 km. When the angle is increased to 45°, the range will increase because the sine function increases as the angle approaches 45°. Thus, the range at 45° is 3.0 km.
Thus, the correct answer is (2).