Question:

The Range of the function \(y=\log (\sin x)\), defined for all \(x\) such that \(\sin x>0\) is ...

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Since sin x lies in (0, 1], take the logarithm of this interval.
Updated On: Nov 12, 2026
  • \((-\infty ,0]\)
  • \((-\infty ,0)\)
  • \(R\)
  • \((0,\infty )\)
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
The function is defined only where \(\sin x>0\).
Also \(\sin x\le1\).

Step 2: Range of the Inner Function
So \(0<\sin x\le1\).

Step 3: Take the Logarithm
The logarithm (base greater than 1) is increasing.
As \(\sin x\to0^{+}\), \(\log(\sin x)\to-\infty\).
At \(\sin x=1\), \(\log 1=0\).

Step 4: Compare the options
So \(y\in(-\infty,0]\), option (A).

Final Answer:
The range is all values up to and including zero. \[ \boxed{\text{(A) }(-\infty ,0]} \]
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