Question:

The range of the function f(x)=x²-x+1x²+x+1, where xR, is:

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Use discriminant condition to find range.
Updated On: Mar 17, 2026
  • (-∞,3]
  • (-∞,∞)
  • [3,∞)
  • [\frac13,3]
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The Correct Option is D

Solution and Explanation

Let y=x²-x+1x²+x+1. y(x²+x+1)=x²-x+1 (y-1)x²+(y+1)x+(y-1)=0 For real x, discriminant \ge0: (y+1)²-4(y-1)²\ge0 3y²-10y+3\le0 (y-3)(3y-1)\le0 \frac13 y\le3
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