Question:
The random variable X has the following probability distribution
|c|c|c|c|c|c|
x & 0 & 1 & 2 & 3 & 4
P(X=x) & k & 3k & 5k & 2k & k
Then the value of P(X\ge2) is
The random variable X has the following probability distribution
|c|c|c|c|c|c|
x & 0 & 1 & 2 & 3 & 4
P(X=x) & k & 3k & 5k & 2k & k
Then the value of P(X\ge2) is
P(X=x) & k & 3k & 5k & 2k & k
Then the value of P(X\ge2) is
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Always normalize probabilities first.
Updated On: Mar 17, 2026
- \frac13
- \frac23
- \frac34
- \frac14
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The Correct Option is B
Solution and Explanation
Total probability:
12k=1 k=\frac112
P(X\ge2)=5k+2k+k=8k=\frac23
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