To solve the problem, we need to determine how much the volume of a sphere increases when its radius is increased by 100%.
1. Original Volume of the Sphere:
The volume of a sphere is given by:
$ V = \frac{4}{3} \pi r^3 $
2. New Radius After 100% Increase:
100% increase in radius means the new radius becomes:
$ r' = r + 1.0r = 2r $
3. New Volume of the Sphere:
$ V' = \frac{4}{3} \pi (2r)^3 = \frac{4}{3} \pi \cdot 8r^3 = 8 \cdot \left(\frac{4}{3} \pi r^3\right) = 8V $
4. Percentage Increase in Volume:
Increase = $ V' - V = 8V - V = 7V $
Percentage increase = $ \frac{7V}{V} \times 100 = 700\% $
Final Answer:
The volume is increased by $ {700\%} $.
List-I | List-II | ||
| (A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
| (B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
| (C) | Volume of Frustum | (III) | \(\pi r^2h\) |
| (D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |