To solve the problem, we need to find the volume of a sphere whose radius is given as $2r$.
1. Volume Formula for a Sphere:
The volume $V$ of a sphere is given by the formula:
$ V = \frac{4}{3} \pi r^3 $
2. Substituting Radius as $2r$:
If radius = $2r$, then the volume becomes:
$ V = \frac{4}{3} \pi (2r)^3 $
$ = \frac{4}{3} \pi (8r^3) $
$ = \frac{32}{3} \pi r^3 $
Final Answer:
The volume of the sphere is $ {\frac{32}{3} \pi r^3} $
List-I | List-II | ||
| (A) | Volume of cone | (I) | \(\frac{1}{3}\pi h(r_1^2+r_2^2+r_1r_2)\) |
| (B) | Volume of sphere | (II) | \(\frac{1}{3}\pi r^2h\) |
| (C) | Volume of Frustum | (III) | \(\pi r^2h\) |
| (D) | Volume of cylinder | (IV) | \(\frac{4}{3}\pi r^3\) |