Question:

The radius of the first orbit of \(\mathrm{He^+}\) is

Show Hint

For hydrogen-like atoms: - Radius decreases with increasing atomic number $Z$ - $r \propto \frac{1}{Z}$
Updated On: Apr 30, 2026
  • $52.9$ pm
  • $13.24$ pm
  • $211.6$ pm
  • $105.8$ pm
  • $26.45$ pm
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is

Solution and Explanation

Concept: Bohr radius for hydrogen-like atoms: \[ r_n = \frac{n^2 a_0}{Z} \] where $a_0 = 52.9$ pm.

Step 1:
Identify values.
\[ n = 1, \quad Z = 2 \; (\text{for He}^+) \]

Step 2:
Substitute.
\[ r_1 = \frac{1^2 \times 52.9}{2} = 26.45\ \text{pm} \]
Was this answer helpful?
0
0