Step 1: The ionic radius generally decreases across a period as the effective nuclear charge increases.
Step 2: Since \( \text{Lu}^{3+} \) is further across the periodic table than \( \text{La}^{3+} \), its radius is smaller. The closest value for the radius of \( \text{Lu}^{3+} \) is 0.85 Å.
Final Answer:
\[
\boxed{0.85 \, \text{Å}}
\]