Question

The products X and Y in the following reaction sequence, respectively, are

• A. B₃N₃Cl₆ and B₃N3H₆
• B. B₃N₃H₃Cl₃ and B₃N₃H₆
• C. B₃N₃H₃Cl₃ and B₃N₃H₁₂
• D. B₃N₃H₉Cl₃ and B₃N₃H₁₂

Answer 1

The Correct Option is B

To determine the products X and Y in the given reaction sequence, we need to analyze the chemical reactions step-by-step.

Step 1: Formation of Compound X 

The initial reaction involves \(BCl_3\) with \(NH_4Cl\) in \(C_6H_5Cl\) at \(150^\circ C\). This setup typically leads to the formation of a chlorinated borazine compound.

• Borazine-like structures form when boron (B) combines with nitrogen (N) in a ring, similar to benzene but with alternating B and N atoms.
• This reaction sequence leads to the formation of trichloroborazine: \(B_3N_3H_3Cl_3\), as chlorine replaces hydrogen in the initial ammonia-borane structure.

Step 2: Reduction to Form Compound Y

The next step involves treating the product with \(NaBH_4\), a reducing agent.

• \(NaBH_4\) reduces \(B_3N_3H_3Cl_3\) to borazine (\(B_3N_3H_6\)).
• The chlorine atoms are replaced by hydrogen, resulting in the fully hydrogenated form of borazine.

Conclusion

The products X and Y in this reaction sequence are:

• X: \(B_3N_3H_3Cl_3\)
• Y: \(B_3N_3H_6\)

Therefore, the correct answer is: B₃N₃H₃Cl₃ and B₃N₃H₆.