Question:
The products obtained by the ozonolysis of 2-ethylbut-1-ene are
The products obtained by the ozonolysis of 2-ethylbut-1-ene are
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To find ozonolysis products instantly, draw a line through the double bond and place an 'O' on each end of the cut. If one carbon of the double bond has two hydrogens, you will always get methanal!
Updated On: May 6, 2026
- propanone and ethanal
- ethanal and 3-pentanone
- butanal and ethanal
- methanal and 2-pentanone
- methanal and 3-pentanone
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The Correct Option is
Solution and Explanation
Concept: Ozonolysis is an organic reaction where the unsaturated bonds of alkenes are cleaved with ozone ($O_3$) to form carbonyl compounds.
• Reaction Mechanism: Ozone adds across the double bond to form an ozonide intermediate.
• Cleavage: In the presence of Zinc and water ($Zn/H_2O$), the ozonide is cleaved precisely at the original double bond position.
• Shortcut: Replace the double bond ($C=C$) with two carbonyl groups ($C=O$ and $O=C$).
Step 1: Identify the structure of 2-ethylbut-1-ene. The parent chain is "butene" (4 carbons). "1-ene" means the double bond is at the first carbon. "2-ethyl" means an ethyl group ($-CH_2CH_3$) is attached to the second carbon. Structure: $CH_2 = C(CH_2CH_3)_2$. Expanding the substituents: The second carbon is attached to two ethyl groups.
Step 2: Cleave the double bond. Cleaving $CH_2 = C(Et)_2$ results in: 1. Fragment from the $=CH_2$ end: $HCHO$ (Methanal or Formaldehyde). 2. Fragment from the other end: $O=C(CH_2CH_3)_2$. This second molecule is a ketone with 5 carbons, specifically 3-pentanone (also known as diethyl ketone).
• Reaction Mechanism: Ozone adds across the double bond to form an ozonide intermediate.
• Cleavage: In the presence of Zinc and water ($Zn/H_2O$), the ozonide is cleaved precisely at the original double bond position.
• Shortcut: Replace the double bond ($C=C$) with two carbonyl groups ($C=O$ and $O=C$).
Step 1: Identify the structure of 2-ethylbut-1-ene. The parent chain is "butene" (4 carbons). "1-ene" means the double bond is at the first carbon. "2-ethyl" means an ethyl group ($-CH_2CH_3$) is attached to the second carbon. Structure: $CH_2 = C(CH_2CH_3)_2$. Expanding the substituents: The second carbon is attached to two ethyl groups.
Step 2: Cleave the double bond. Cleaving $CH_2 = C(Et)_2$ results in: 1. Fragment from the $=CH_2$ end: $HCHO$ (Methanal or Formaldehyde). 2. Fragment from the other end: $O=C(CH_2CH_3)_2$. This second molecule is a ketone with 5 carbons, specifically 3-pentanone (also known as diethyl ketone).
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