Question:

The product of the following reaction,
{C$_6$H$_5$COCH$_2$Br$_2$ + OH$^-$}.....

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In nucleophilic substitution reactions with bromine, the hydroxide ion replaces the bromine, leading to the formation of the corresponding aldehyde or acid.
Updated On: Apr 22, 2026
  • \( \text{C}_6\text{H}_5\text{COCHO} \)
    (2) \( \text{C}_6\text{H}_5\text{COOH} \)
    (3) \( \text{C}_6\text{H}_5\text{CHO} \)
    (4) \( \text{C}_6\text{H}_5\text{COOHCOOH} \)
  • \( \text{C}_6\text{H}_5\text{COOH} \)
    \( \text{C}_6\text{H}_5\text{CHO} \)
    \( \text{C}_6\text{H}_5\text{COOHCOOH} \)
  • \( \text{C}_6\text{H}_5\text{CHO} \)
    \( \text{C}_6\text{H}_5\text{COOHCOOH} \)
  • \( \text{C}_6\text{H}_5\text{COOHCOOH} \)
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The Correct Option is A

Solution and Explanation

Step 1: Analyze the reaction.
The reaction involves a carbonyl compound (benzoyl group \( \text{C}_6\text{H}_5\text{CO} \)) with two bromine atoms attached to a carbon. The reaction with hydroxide ions (\( OH^- \)) suggests a nucleophilic substitution.

Step 2: Mechanism of the reaction.

The hydroxide ion (\( OH^- \)) attacks the electrophilic carbon attached to the bromine, replacing the bromine atom. The two bromine atoms are replaced by a single hydroxyl group, resulting in the formation of an aldehyde group.

Step 3: Conclusion.

The correct product is \( \text{C}_6\text{H}_5\text{COCHO} \) (benzaldehyde), which corresponds to option (1).
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