Question

The product formed when phthalimide is treated with a mixture of \( \text{Br}_2 \) and strong NaOH solution is:

• A. aniline
• B. phthalamide
• C. phthalic acid
• D. anthranilic acid

Hint:

The reaction of phthalimide with \( \text{Br}_2 \) and NaOH typically results in the formation of anthranilic acid.

Answer 1

The Correct Option is D

Step 1: Reaction with \( \text{Br}_2 \) and NaOH.
The reaction of phthalimide with \( \text{Br}_2 \) and NaOH leads to the formation of anthranilic acid through a nucleophilic substitution.
Step 2: Explanation.
Thus, phthalimide reacts with bromine and NaOH to produce anthranilic acid.
Final Answer: \[ \boxed{\text{D) anthranilic acid}} \]