Question:
The product formed in the following reaction is: $ C{{H}_{3}}CH(C{{H}_{3}})CH=C{{H}_{2}}+HBr $ $ \xrightarrow{{}}product: $
The product formed in the following reaction is: $ C{{H}_{3}}CH(C{{H}_{3}})CH=C{{H}_{2}}+HBr $ $ \xrightarrow{{}}product: $
Updated On: Jun 6, 2022
- $ {{(C{{H}_{3}})}_{2}}CHCH(Br)C{{H}_{3}} $
- $ {{(C{{H}_{3}})}_{2}}CHC{{H}_{2}}C{{H}_{2}}Br $
- $ {{(C{{H}_{3}})}_{2}}C(Br)C{{H}_{2}}C{{H}_{3}} $
- $ C{{H}_{3}}CH(C{{H}_{3}})CH(Br)C{{H}_{2}}C{{H}_{3}} $
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
The addition of HBr is according to Markownikoff s rule in this reaction. $ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-CH=C{{H}_{2}}+\overset{+\,\,\,-}{\mathop{HBr}}\,\xrightarrow{{}} $ $ C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,-\underset{\begin{smallmatrix} | \\ Br \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{3}} $
Was this answer helpful?
0
0
Top KEAM Chemistry Questions
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
- $4\, g$ of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave $5\, g$ of its oxide. The equivalent weight of copper is :
- Green chemistry deals with
- Neopentyl bromide undergoes dehydrohalogenation to give alkenes even though it has no $\beta$- hydrogen. This is due to
- Plot of $ log\text{ }x/m $ against log $p$ is a straight line inclined at an angle of $ 45{}^\circ $ . When the pressure is $ 0.5 \,arm $ and Freundlich parameter. $ k $ is $ 10 $ , the amount of solute adsorbed per gram of adsorbent will be $ (log\text{ }5=0.6990) $
View More Questions
Top KEAM Alkenes Questions
- An alkene $ {{C}_{4}}{{H}_{8}} $ , was treated with ozone and then with zinc and water to give acetone and formaldehyde. The alkene is:
- The reaction of propene with $HBr$ in peroxide proceeds through the intermediate
- One mole of propanone and one mole of formaldehyde are the products of ozonolysis of one mole of an alkene. The alkene may be
- The product obtained on ozonolysis of 3-Ethylpent-2-ene are
Top KEAM Questions
- i.$\quad$ They help in respiration ii.$\quad$ They help in cell wall formation iii.$\quad$ They help in DNA replication iv. $\quad$They increase surface area of plasma membrane Which of the following prokaryotic structures has all the above roles?
- A body oscillates with SHM according to the equation (in SI units), $x = 5 cos \left(2\pi t +\frac{\pi}{4}\right) .$ Its instantaneous displacement at $t = 1$ second is
- The pH of a solution obtained by mixing 60 mL of 0.1 M BaOH solution at 40m of 0.15m HCI solution is
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
- If $\int e^{2x}f' \left(x\right)dx =g \left(x\right)$, then $ \int\left(e^{2x}f\left(x\right) + e^{2x} f' \left(x\right)\right)dx =$
View More Questions
Concepts Used:
Alkenes
Alkenes
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
IUPAC Nomenclature of Alkenes
- An alkene or cycloalkene is indicated by the suffix (ending) ene.
- For the root name, the longest chain must include both carbon atoms of the double bond.
- The root chain must be numbered beginning at the end closest to a double bond carbon atom. If the double bond is in the chain's centre, the nearest substituent rule is used to determine where the numbering begins.
- If the compound contains more than one double bond, it is named with a diene, triene, or equivalent prefix indicating the number of double bonds, and each double bond is assigned a locator number.
Read More: Unsaturated Hydrocarbon