Question:

The product formed in the following reaction is

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Key strategy: - Protect –NH$_2$ before Friedel–Crafts - –NHCOCH$_3$ is ortho/para directing - Para product dominates due to less steric hindrance
Updated On: May 1, 2026
  • A
  • B
  • C
  • D
  • E
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The Correct Option is A

Solution and Explanation


Concept: This reaction involves two important organic transformations:
• Protection of amine group (acetylation)
• Friedel–Crafts acylation (electrophilic aromatic substitution)

Step 1: Acetylation of Aniline
\[ C_6H_5NH_2 + (CH_3CO)_2O \rightarrow C_6H_5NHCOCH_3 \]
• The –NH$_2$ group is highly activating and can lead to side reactions
• Hence it is protected as –NHCOCH$_3$ (acetanilide)
• This reduces its reactivity and avoids complex formation with AlCl$_3$ Important:
• –NHCOCH$_3$ is still an ortho/para directing group
• Para position is favored due to less steric hindrance

Step 2: Friedel–Crafts Acylation
Reagent: \[ \text{ClCH}_2\text{COCl} / AlCl_3 \]
• Generates electrophile: \(\text{ClCH}_2CO^+\)
• This electrophile attacks aromatic ring Orientation:
• –NHCOCH$_3$ directs substitution to ortho and para positions
• Para product dominates due to steric factors Final Product Formation:
• Acyl group (–COCH$_2$Cl) attaches at para position
• Amide group remains intact Thus structure corresponds to option (A) Why other options are incorrect:
• (B) Incorrect positioning wrong substitution
• (C), (D), (E) show either:
• Unprotected amine (not possible under AlCl$_3$)
• Wrong directing behavior
• Multiple substitutions inconsistent with mechanism Conclusion: \[ \text{Major product is para-substituted acetanilide derivative} \]
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