Question:
The probability that a person hits a target is \(0.6\). If he fires \(5\) shots at the target, then the probability that he hits the target at least once is
The probability that a person hits a target is \(0.6\). If he fires \(5\) shots at the target, then the probability that he hits the target at least once is
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Use the complement: one minus the probability of missing every shot.
Updated On: Nov 12, 2026
- \(0.96912\)
- \(0.46980\)
- \(0.89716\)
- \(0.98976\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
For repeated independent shots, \(P(\text{at least one hit})=1-P(\text{no hit})\).
Step 2: Compute the miss probability
The chance of missing one shot is \(1-0.6=0.4\), so missing all five shots has probability \(0.4^{5}=0.01024\).
Step 3: Subtract
\(1-0.01024=0.98976\).
Final Answer:
The probability is \(0.98976\). \[ \boxed{\text{(D) }0.98976} \]
For repeated independent shots, \(P(\text{at least one hit})=1-P(\text{no hit})\).
Step 2: Compute the miss probability
The chance of missing one shot is \(1-0.6=0.4\), so missing all five shots has probability \(0.4^{5}=0.01024\).
Step 3: Subtract
\(1-0.01024=0.98976\).
Final Answer:
The probability is \(0.98976\). \[ \boxed{\text{(D) }0.98976} \]
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