Question:

The probability that a non leap year selected at random will contain 52 Saturdays or 53 Sundays is

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A non-leap year has 52 weeks and one extra day; use the union formula for the two events.
Updated On: Nov 13, 2026
  • \(\frac{1}{7}\)

  • \(\frac{6}{7}\)

  • \(\frac{2}{7}\)

  • \(\frac{5}{7}\)

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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
365 days = 52 weeks + 1 extra day, and each of the 7 weekdays is equally likely to be the extra day.

Step 2: Find the probabilities
\(P(52\text{ Saturdays})=P(\text{extra day is not Saturday})=\dfrac{6}{7}\).
\(P(53\text{ Sundays})=\dfrac{1}{7}\).

Step 3: Intersection
Both hold if the extra day is Sunday: \(P=\dfrac{1}{7}\).

Step 4: Union
\(P=\dfrac{6}{7}+\dfrac{1}{7}-\dfrac{1}{7}=\dfrac{6}{7}\).

Final Answer:
The probability is 6/7. \[ \boxed{\text{(B) }\dfrac{6}{7}} \]
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