Question

The probability of getting 10 in a single throw of three fair dice is:

• A. \(\dfrac{1}{6}\)
• B. \(\dfrac{1}{8}\)
• C. \(\dfrac{1}{9}\)
• D. (1)/(5)

Hint:

Always count ordered outcomes for dice probability.

Answer 1

The Correct Option is C

Step 1: Total outcomes =6³=216.
Step 2: Favourable combinations for sum 10: (1,3,6),(1,4,5),(2,2,6),(2,3,5),(2,4,4),(3,3,4)
Step 3: Counting permutations gives 24 favourable outcomes.
Step 4: P=(24)/(216)=(1)/(9)