Question

The preferred slip plane for FCC is

• A. (101)
• B. (111)
• C. (100)
• D. (000)

Hint:

FCC = 111. High-density planes are the easiest for atoms to "slide" over each other.

Answer 1

The Correct Option is B

Step 1: Concept Slip occurs on the most densely packed planes and in the most densely packed directions within a crystal lattice.

Step 2: Meaning Densely packed planes have the largest interplanar spacing and require the least amount of shear stress to initiate dislocation movement.

Step 3: Analysis In the Face-Centered Cubic (FCC) system, the closest-packed planes are the octahedral planes.

Step 4: Conclusion These close-packed planes are represented by the Miller indices $\{111\}$. Final Answer: (B)