Question:
The power radiated by a black body is P and it radiates maximum energy at wavelength, λ0 . If the temperature of the black body is now changed so that it radiates maximum energy at wavelength \(\frac{3}{4}\lambda_0\), the power radiated by it becomes nP. The value of n is
The power radiated by a black body is P and it radiates maximum energy at wavelength, λ0 . If the temperature of the black body is now changed so that it radiates maximum energy at wavelength \(\frac{3}{4}\lambda_0\), the power radiated by it becomes nP. The value of n is
Updated On: Apr 24, 2026
- \(\frac{3}{4}\)
- \(\frac{256}{81}\)
- \(\frac{4}{3}\)
- \(\frac{81}{256}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac{256}{81}\)
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