Step 1: Compute equivalent resistance in series.
10 resistors each \(R = 1 \, \Omega\) in series:
\[
R_s = 10 \times 1 = 10 \, \Omega
\]
Step 2: Compute power in series.
\[
P_s = \frac{V^2}{R_s} = \frac{10^2}{10} = 10 \, \text{W}
\]
Step 3: Compute equivalent resistance in parallel.
10 resistors each \(1 \, \Omega\) in parallel:
\[
\frac{1}{R_p} = 10 \cdot \frac{1}{1} = 10 \implies R_p = 0.1 \, \Omega
\]
Step 4: Compute power in parallel.
\[
P_p = \frac{V^2}{R_p} = \frac{10^2}{0.1} = 1000 \, \text{W}
\]
Step 5: Compute ratio.
\[
\frac{P_s}{P_p} = \frac{10}{1000} = 0.01
\]
Step 6: Final conclusion.
Hence, the ratio of power in series to parallel combination is:
\[
\boxed{0.01}
\]