Question

The potential gradient along the length of 1 metre wire of uniform cross section is \(6\text{ V/m}\). Let '\(B\)' and '\(C\)' be the two points at \(40\text{ cm}\) and \(60\text{ cm}\) marks respectively from one end. The potential difference between points B and C is

• A. \(1.2\text{ V}\)
• B. \(2.4\text{ V}\)
• C. \(3.5\text{ V}\)
• D. \(6.0\text{ V}\)

Hint:

Potential difference equals the potential gradient times the distance between the two points.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
Along a uniform potentiometer wire the potential drop is proportional to the length, so \(V=\text{gradient}\times\text{length}\).

Step 2: Find the Length
Distance between B and C \(=60-40=20\text{ cm}=0.2\text{ m}\).

Step 3: Calculation
\(V=6\times0.2=1.2\text{ V}\)

Step 4: Compare the options
This is the first option.

Final Answer:
The potential difference between B and C is 1.2 V. \[ \boxed{\text{(A) }1.2\text{ V}} \]