Question:

The position vectors of the points $A$ and $B$ are $\vec{a} = 2\hat{i} - \lambda \hat{j} + 5\hat{k}$ and $\vec{b} = \mu \hat{i} + 7\hat{j} + 3\hat{k}$ respectively. If the position vector of the mid-point of the line segment $AB$ is $\vec{c} = 3\hat{i} + 2\hat{j} + 4\hat{k}$, then the value of $\lambda + \mu$ is equal to

Show Hint

For midpoint vector problems, simply add corresponding components of the endpoint vectors and divide by two. It is identical to the midpoint formula in coordinate geometry.
Updated On: Jun 26, 2026
  • 6
  • 7
  • 8
  • 9
  • 10
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
The position vector of the mid-point of a line segment connecting two points with position vectors \( \vec{a} \) and \( \vec{b} \) is \( \vec{c} = \frac{\vec{a} + \vec{b}}{2} \).

Step 2: Detailed Explanation:

\[ \vec{c} = \frac{(2\hat{i} - \lambda \hat{j} + 5\hat{k}) + (\mu \hat{i} + 7\hat{j} + 3\hat{k})}{2} \]
\[ \vec{c} = \frac{2 + \mu}{2}\hat{i} + \frac{7 - \lambda}{2}\hat{j} + \frac{8}{2}\hat{k} \]
Given \( \vec{c} = 3\hat{i} + 2\hat{j} + 4\hat{k} \).
Comparing components:
\( \hat{i} \) component: \( \frac{2 + \mu}{2} = 3 \implies 2 + \mu = 6 \implies \mu = 4 \)
\( \hat{j} \) component: \( \frac{7 - \lambda}{2} = 2 \implies 7 - \lambda = 4 \implies \lambda = 3 \)
Calculating \( \lambda + \mu \):
\[ 3 + 4 = 7 \]

Step 3: Final Answer:

The value of \( \lambda + \mu \) is 7.
Was this answer helpful?
0
0