Step 1: {Find slopes between points}
Using slope formula:
\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]
Step 2: {Calculate slopes}
\[
m_{AB} = \frac{3 - 1}{-2 - 1} = -\frac{2}{3}
\]
\[
m_{BC} = \frac{\frac{5}{3} - 3}{0 - (-2)} = -\frac{2}{3}
\]
Step 3: {Conclusion}
Since all slopes are the same, the points are collinear.
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Approach Solution -2
Step 1: Identify the points on the Argand plane
The complex numbers correspond to points:
\(A = (1, 1)\), \(B = (-2, 3)\), and \(C = (0, \frac{5}{3})\).
Step 2: Use the slope formula to check collinearity
Calculate slope of line \(AB\):
\[
m_{AB} = \frac{3 - 1}{-2 - 1} = \frac{2}{-3} = -\frac{2}{3}
\]
Calculate slope of line \(BC\):
\[
m_{BC} = \frac{\frac{5}{3} - 3}{0 - (-2)} = \frac{\frac{5}{3} - \frac{9}{3}}{2} = \frac{-\frac{4}{3}}{2} = -\frac{2}{3}
\]
Step 3: Conclusion
Since \(m_{AB} = m_{BC} = -\frac{2}{3}\), the points are collinear.