Step 1: pOH and concentration relation.
The pOH is related to the hydroxide ion concentration \( [OH^-] \) by the equation:
\[
\text{pOH} = -\log [OH^-]
\]
Substituting the given concentration \( 6.2 \times 10^{-9} \, \text{mol/litre} \), we get:
\[
\text{pOH} = -\log (6.2 \times 10^{-9}) = 8.21
\]
Thus, the correct answer is (1).