Question:

The period of θ+\sin2θθ+\cos2θ is:

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Reduce expressions to standard trig functions.
Updated On: Mar 17, 2026

  • π
  • 2π3
  • π3
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The Correct Option is A

Solution and Explanation

Using sum-to-product formulas: 2(3θ)/(2)(θ)/(2) 2(3θ)/(2)(θ)/(2) =(3θ)/(2) Period of x is π, hence (3θ)/(2)=π θ=(2π)/(3) Overall fundamental period is 2π.
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