Question:

The passage of blood in circularly system is : \[ \begin{aligned} A.&\ \text{IVC} B.&\ \text{Right Atrium} C.&\ \text{Left Atrium} D.&\ \text{Right ventricle} E.&\ \text{Left ventricle} \end{aligned} \] Choose the correct answer from the options given below :

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The right side of the heart carries deoxygenated blood, while the left side carries oxygenated blood.
Updated On: May 20, 2026
  • A, D, E, B, C
  • A, B, D, C, E
  • A, B, D, E, C
  • A, D, B, C, E
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The Correct Option is B

Solution and Explanation

Concept: The circulatory system transports blood throughout the body. Deoxygenated blood from the body enters the heart through the Inferior Vena Cava (IVC), then passes through the right side of the heart to the lungs, and oxygenated blood returns to the left side of the heart. The simplified pathway of blood circulation is: \[ \text{IVC} \rightarrow \text{Right Atrium} \rightarrow \text{Right Ventricle} \rightarrow \text{Left Atrium} \rightarrow \text{Left Ventricle} \]

Step 1:
Identify the starting point of circulation.
Blood from the lower body enters the heart through: \[ \text{IVC} \]

Step 2:
Follow the flow of blood through the heart.
The sequence continues as: \[ \text{Right Atrium} \rightarrow \text{Right Ventricle} \] After oxygenation in the lungs, blood returns to: \[ \text{Left Atrium} \rightarrow \text{Left Ventricle} \]

Step 3:
Choose the correct sequence.
Thus, the correct order is: \[ A, B, D, C, E \] Hence, the correct answer is: \[ \boxed{(B)\ A, B, D, C, E} \]
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