- Torque is given by \( {Torque} = {Force} \times {Distance} \), so its dimensional formula is \( [M L^2 T^{-2}] \).
- Energy is given by \( {Energy} = {Force} \times {Distance} \), so its dimensional formula is also \( [M L^2 T^{-2}] \). Hence, Torque and Energy have the same dimensions, and the correct answer is not option (1). Let's check other options to make sure.
- Pressure is given by \( {Pressure} = \frac{{Force}}{{Area}} \), so its dimensional formula is \( [M L^{-1} T^{-2}] \).
- Young’s modulus is given by \( {Young's modulus} = \frac{{Stress}}{{Strain}} \), and its dimensional formula is also \( [M L^{-1} T^{-2}] \). Thus, Pressure and Young’s modulus have the same dimensions.
- Angular momentum has dimensions \( [M L^2 T^{-1}] \) and Planck's constant has dimensions \( [M L^2 T^{-1}] \), so they have the same dimensions.
- Surface tension has dimensions \( [M T^{-2}] \) and impulse has dimensions \( [M L T^{-1}] \), so they do not have the same dimensions. Thus, the correct answer is option (1).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


A convex mirror of radius of curvature 30 cm forms an image that is half the size of the object. The object distance is:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)