Question:
The oxidation states of sulphur in the anions SO₃²⁻, S₂O₄²⁻ and S₂O₆²⁻ follow the order
The oxidation states of sulphur in the anions SO₃²⁻, S₂O₄²⁻ and S₂O₆²⁻ follow the order
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Always calculate oxidation state algebraically.
Updated On: Mar 17, 2026
- SO₃²⁻ < S₂O₄²⁻ < S₂O₆²⁻
- S₂O₄²⁻ < S₂O₆²⁻ < SO₃²⁻
- S₂O₆²⁻ < S₂O₄²⁻ < SO₃²⁻
- S₂O₄²⁻ < SO₃²⁻ < S₂O₆²⁻
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Oxidation states of S are:
SO₃²⁻: +4,
S₂O₄²⁻: +3,
S₂O₆²⁻: +5.
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