
To determine when the output \( Y \) of the given logic circuit is 0, we analyze the circuit’s components and their behavior with inputs \( A \) and \( B \).
Step 1: Identifying Logic Gates
From the circuit:
- There is an OR gate taking inputs \( A \) and \( B \).
- Another OR gate takes input from the output of the first OR gate and a constant input 1.
- There is an AND gate with inputs \( A \) and \( B \), whose output feeds into the final OR gate.
Step 2: Analyzing the Behavior of the Circuit
1. The first OR gate outputs 1 if either \( A = 1 \) or \( B = 1 \). The output of this OR gate is 0 only if both \( A = 0 \) and \( B = 0 \).
2. The second OR gate has one input fixed as 1. Since an OR gate outputs 1 if any input is 1, this gate will always output 1 regardless of the input from the first OR gate.
3. The AND gate outputs 1 only if both \( A = 1 \) and \( B = 1 \). In all other cases, it outputs 0.
4. The output \( Y \) is determined by the final OR gate, which takes inputs from the AND gate and the second OR gate. Since the second OR gate always outputs 1, the only way for \( Y \) to be 0 is for all other inputs (AND gate output) to be 0.
Step 3: Condition for \( Y = 0 \)
For the output \( Y \) to be 0, the input conditions must be such that the output from the AND gate is 0 (which happens when \( A = 0 \) and \( B = 0 \)).
Therefore, the correct condition is:
\[ A = 0, \, B = 0. \]
Hence, the correct option is (2).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


Draw truth table of given gate circuit.


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)