




A NAND gate produces an output that is the negation of the AND gate output. The output (\( Y \)) is given by: \[ Y = \overline{A \cdot B}, \] where \( A \) and \( B \) are the inputs to the NAND gate. The truth table for a NAND gate is as follows:

Step-by-Step Analysis of the Inputs and Outputs: - When both \( A = 0 \) and \( B = 0 \), the output \( Y = 1 \).
- When \( A = 0 \) and \( B = 1 \), the output \( Y = 1 \). - When \( A = 1 \) and \( B = 0 \), the output \( Y = 1 \).
- When both \( A = 1 \) and \( B = 1 \), the output \( Y = 0 \).
Now analyze the given input waveforms for \( A \) and \( B \):
1. For each interval where \( A \) and \( B \) are given, calculate \( A \cdot B \).
2. Take the negation (\( \overline{A \cdot B} \)) to find the output \( Y \).
From the given inputs and truth table, the output waveform matches Option (2).
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


Draw truth table of given gate circuit.


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)