Question:

The number of sigma (\( \sigma \)) and pi (\( \pi \)) bonds present in 3-Methylbut-1-ene are respectively

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Double bond always contributes one $\pi$ bond.
Updated On: Apr 21, 2026
  • \(1 \text{ and } 14 \)
  • \(18 \text{ and } 2 \)
  • \(16 \text{ and } 2 \)
  • \(17 \text{ and } 1 \)
  • \(14 \text{ and } 1 \)
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The Correct Option is

Solution and Explanation

Concept: Single bond $= 1\sigma$, Double bond $= 1\sigma + 1\pi$.

Step 1:
Structure.
3-Methylbut-1-ene $\rightarrow$ one double bond.

Step 2:
Count.
\[ \pi = 1,\quad \sigma = 14 \]
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