Question:
The number of geometrical isomers of CH₃–CH=CH–CH=CHCl is
The number of geometrical isomers of CH₃–CH=CH–CH=CHCl is
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Each independent double bond gives two geometrical possibilities.
Updated On: Mar 18, 2026
- 2
- 4
- 6
- 8
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The Correct Option is B
Solution and Explanation
Step 1: Two C=C bonds are present.
Step 2: Each double bond shows E/Z isomerism. Total = 2² = 4
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