Question:
The number of diagonals in a hexagon is:
The number of diagonals in a hexagon is:
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From each vertex, diagonals = \( n-3 \). Multiply by \( n \) and divide by 2 to avoid double counting.
Updated On: May 1, 2026
- \( 8 \)
- \( 9 \)
- \( 10 \)
- \( 11 \)
- \( 12 \)
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The Correct Option is B
Solution and Explanation
Concept: A diagonal connects two non-adjacent vertices of a polygon. Total ways to choose 2 vertices = \( \binom{n}{2} \), but this includes sides. So, number of diagonals: \[ \frac{n(n-3)}{2} \]
Step 1: Identify number of vertices.
For a hexagon: \[ n = 6 \]
Step 2: Apply the formula.
\[ \text{Diagonals} = \frac{6(6-3)}{2} \] \[ = \frac{6 \times 3}{2} \]
Step 3: Simplify.
\[ = \frac{18}{2} = 9 \]
Step 4: Final answer.
\[ \boxed{9} \]
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