Question:
The number of carbon atoms per molecule of citric acid, oxaloacetic acid and pyruvic acid respectively are _________
The number of carbon atoms per molecule of citric acid, oxaloacetic acid and pyruvic acid respectively are _________
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Remember: Glycolysis produces 3-carbon pyruvate, while the Krebs cycle starts with 6-carbon citrate.
Updated On: Mar 28, 2026
- 4, 6 and 3
- 6, 4 and 3
- 6, 3 and 2
- 4, 4 and 3
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The Correct Option is B
Solution and Explanation
Step 1: Understanding metabolic intermediates.
Citric acid, oxaloacetic acid, and pyruvic acid are important intermediates of cellular respiration.
Step 2: Counting carbon atoms.
Citric acid is a six-carbon compound formed by the condensation of acetyl-CoA and oxaloacetate.
Oxaloacetic acid contains four carbon atoms.
Pyruvic acid is a three-carbon compound formed during glycolysis.
Step 3: Conclusion.
Thus, the correct order of carbon atoms is 6, 4, and 3.
Citric acid, oxaloacetic acid, and pyruvic acid are important intermediates of cellular respiration.
Step 2: Counting carbon atoms.
Citric acid is a six-carbon compound formed by the condensation of acetyl-CoA and oxaloacetate.
Oxaloacetic acid contains four carbon atoms.
Pyruvic acid is a three-carbon compound formed during glycolysis.
Step 3: Conclusion.
Thus, the correct order of carbon atoms is 6, 4, and 3.
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