Question:
The number of bonding pairs and lone pairs of electrons in \(\mathrm{BrF_5}\) molecule are respectively
The number of bonding pairs and lone pairs of electrons in \(\mathrm{BrF_5}\) molecule are respectively
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For central atom:
- Lone pairs = $\frac{\text{valence electrons} - \text{bond pairs}}{2}$
Updated On: Apr 30, 2026
- $4$ and $2$
- $3$ and $2$
- $4$ and $1$
- $5$ and $1$
- $3$ and $1$
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The Correct Option is D
Solution and Explanation
Concept:
Central atom $\mathrm{Br}$ has $7$ valence electrons.
Step 1: Count bonding pairs.
$\mathrm{BrF_5}$ has $5$ Br--F bonds: \[ \Rightarrow 5 \text{ bonding pairs} \]
Step 2: Find lone pairs.
Total valence electrons of Br = $7$
Used in bonding = $5$
Remaining = $2$ electrons $\Rightarrow 1$ lone pair
Step 3: Conclusion.
\[ \text{Bonding pairs} = 5,\quad \text{Lone pairs} = 1 \]
Step 1: Count bonding pairs.
$\mathrm{BrF_5}$ has $5$ Br--F bonds: \[ \Rightarrow 5 \text{ bonding pairs} \]
Step 2: Find lone pairs.
Total valence electrons of Br = $7$
Used in bonding = $5$
Remaining = $2$ electrons $\Rightarrow 1$ lone pair
Step 3: Conclusion.
\[ \text{Bonding pairs} = 5,\quad \text{Lone pairs} = 1 \]
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