The number of angular nodes and radial nodes in an orbital can be determined by the following formulas:
1. Angular nodes: The number of angular nodes is equal to \( l \), where \( l \) is the azimuthal quantum number. For a 'd' orbital, \( l = 2 \).
Therefore, the number of angular nodes is:
\[ \text{Angular nodes} = l = 2 \] 2. Radial nodes: The number of radial nodes is given by the formula:
\[ \text{Radial nodes} = n - l - 1 \] where \( n \) is the principal quantum number. For the '4d' orbital, \( n = 4 \) and \( l = 2 \). So, the number of radial nodes is:
\[ \text{Radial nodes} = 4 - 2 - 1 = 1 \]
Thus, the number of angular nodes is 2, and the number of radial nodes is 1.
Therefore, the correct answer is:
\[ \boxed{\text{A) 2, 1}} \]
ΔS would be negative for which of the following reactions?
(I) \( {CaCO}_3(s) \rightarrow {CaO}(s) + {CO}_2(g) \)
(II) \( {Ag}^+(aq) + {Cl}^-(aq) \rightarrow {AgCl}(s) \)
(III) \( {N}_2(g) + 3{H}_2(g) \rightarrow 2{NH}_3(g) \)
Choose the correct answer from the codes given below:
Kepler's second law (law of areas) of planetary motion leads to law of conservation of