Question:
The monomers of Nylon-6,6 are
The monomers of Nylon-6,6 are
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Remember that the numerical designation in "Nylon-n,m" refers to the number of carbon atoms in each monomer, with one being a diamine and the other a dicarboxylic acid.
Updated On: May 31, 2026
- Adipic acid and hexamethylenediamine
- Caprolactam
- Ethylene glycol and terephthalic acid
- Styrene and butadiene
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Nylon-6,6 is a synthetic polymer formed by the condensation reaction between dicarboxylic acids and diamines. The specific monomers determine the numerical designation in its name.
Step 2: Meaning
The term "Nylon-6,6" indicates that this nylon has two different types of monomers: one with 6 carbon atoms (hexamethylene) and another with a carboxyl group (-COOH) attached to it. The number 6 before the comma refers to the diamine having 6 carbon atoms, while the second 6 after the comma indicates that the dicarboxylic acid has 6 carbon atoms.
Step 3: Analysis
Option A: Adipic acid (C6H10O4) and hexamethylenediamine (C6H12N2). This combination matches the description of Nylon-6,6 because adipic acid is a dicarboxylic acid with 6 carbon atoms, and hexamethylenediamine is a diamine with 6 carbon atoms. When these two monomers react, they form a polymer with repeating units of -COO-(CH2)6-NH-. Option B: Caprolactam (C6H11NO). This is the monomer for Nylon-6, but it does not contain both a carboxyl group and an amine group necessary to form Nylon-6,6 through condensation polymerization. Option C: Ethylene glycol (C2H4(OH)2) and terephthalic acid (C8H6O4). This combination forms Polyester rather than Nylon. Ethylene glycol is a diol with 2 carbon atoms, while terephthalic acid has 10 carbon atoms. Option D: Styrene (C8H8) and butadiene (C4H6). These are monomers for producing polystyrene or polybutadiene, not Nylon-6,6.
Step 4: Conclusion
The correct monomers for Nylon-6,6 are adipic acid and hexamethylenediamine as they both have 6 carbon atoms and can undergo condensation polymerization to form the desired polymer structure. Final Answer: (A)
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