Question:

The moment of inertia of a uniform hollow sphere about its diameter is

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Remember standard results: - Solid sphere: $\frac{2}{5}MR^2$ - Hollow sphere (shell): $\frac{2}{3}MR^2$
Updated On: May 13, 2026
  • $MR^2$
  • $\frac{MR^2}{2}$
  • $\frac{2}{3}MR^2$
  • $\frac{3}{2}MR^2$
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The Correct Option is C

Solution and Explanation

Concept: A uniform hollow sphere (thin spherical shell) has a standard moment of inertia about any diameter given by: \[ I = \frac{2}{3}MR^2 \] where $M$ is the mass and $R$ is the radius of the sphere.

Step 1:
Identify the type of body.
The given object is a uniform hollow sphere, meaning mass is distributed only on its surface.

Step 2:
Recall the standard formula.
For a hollow sphere about its diameter: \[ I = \frac{2}{3}MR^2 \]

Step 3:
Match with given options.
The correct expression matches option (C).

Step 4:
Final conclusion.
Thus, the moment of inertia is: \[ \frac{2}{3}MR^2 \]
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