The minimum number of comparators required to build an eight-bit flash ADC is
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The number of comparators required for a flash ADC increases exponentially with the number of bits. For an \( n \)-bit ADC, the number of comparators is \( 2^n - 1 \).
For an \( n \)-bit flash ADC, the minimum number of comparators required is \( 2^n - 1 \). Therefore, for an 8-bit ADC:
\[
2^8 - 1 = 255
\]
Thus, the minimum number of comparators required to build an eight-bit flash ADC is 255. Therefore, the correct answer is option (2).
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