Question:
The metal ion, ligands present in Wilkinson catalyst are respectively
The metal ion, ligands present in Wilkinson catalyst are respectively
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Remember: Wilkinson's catalyst contains Rhodium in the $+1$ oxidation state.
Updated On: Jun 3, 2026
- $Rh^{3+}, Cl^{-}, PPh_{3}$
- $Rh^{+}, Cl^{-}, PPh_{3}$
- $Rh^{2+}, Br^{-}, PPh_{3}$
- $Re^{+}, I^{-}, P(CH_{3})_{3}$
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The Correct Option is B
Solution and Explanation
Step 1: Concept
The Wilkinson's catalyst is a well-known organometallic compound used as a homogeneous catalyst for the hydrogenation of alkenes.
Step 2: Meaning
The chemical formula for Wilkinson's catalyst is $RhCl(PPh_{3})_{3}$, where $Rh$ is Rhodium, $Cl$ is Chlorine, and $PPh_{3}$ is Triphenylphosphine.
Step 3: Analysis
In the complex $RhCl(PPh_{3})_{3}$, the triphenylphosphine ($PPh_{3}$) ligands are neutral and the chloride ($Cl$) ligand has a $-1$ charge. To maintain electrical neutrality, the oxidation state of Rhodium must be $+1$.
Step 4: Conclusion
Therefore, the metal ion is $Rh^{+}$, the ligand is $Cl^{-}$, and the other ligand is $PPh_{3}$.
Final Answer: (B)
The Wilkinson's catalyst is a well-known organometallic compound used as a homogeneous catalyst for the hydrogenation of alkenes.
Step 2: Meaning
The chemical formula for Wilkinson's catalyst is $RhCl(PPh_{3})_{3}$, where $Rh$ is Rhodium, $Cl$ is Chlorine, and $PPh_{3}$ is Triphenylphosphine.
Step 3: Analysis
In the complex $RhCl(PPh_{3})_{3}$, the triphenylphosphine ($PPh_{3}$) ligands are neutral and the chloride ($Cl$) ligand has a $-1$ charge. To maintain electrical neutrality, the oxidation state of Rhodium must be $+1$.
Step 4: Conclusion
Therefore, the metal ion is $Rh^{+}$, the ligand is $Cl^{-}$, and the other ligand is $PPh_{3}$.
Final Answer: (B)
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