The median class of the following table will be: 
Step 1: Find cumulative frequencies. 
Step 2: Determine $N/2$.
\[ N = 49 \Rightarrow N/2 = 24.5 \] Step 3: Identify the median class.
The class in which the cumulative frequency first exceeds 24.5 is 30–40.
Step 4: Conclusion.
Hence, the median class is 30–40.
Find the median of the following data : 
Find the mode of the following frequency table : 
The modal class of the following frequency table will be : 
The median class of the following frequency distribution will be : 