Question:
The mean deviation of the data \( 2, 9, 9, 3, 6, 9, 4 \) from the mean is
The mean deviation of the data \( 2, 9, 9, 3, 6, 9, 4 \) from the mean is
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Mean deviation always uses absolute values of deviations.
Updated On: May 1, 2026
- \( 2.23 \)
- \( 3.23 \)
- \( 2.57 \)
- \( 3.57 \)
- \( 1.03 \)
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The Correct Option is C
Solution and Explanation
Concept:
Mean deviation from mean:
\[
\text{MD} = \frac{1}{n} \sum |x_i - \bar{x}|
\]
Step 1: Find mean.
\[ \bar{x} = \frac{2+9+9+3+6+9+4}{7} = \frac{42}{7} = 6 \]
Step 2: Compute deviations.
\[ |2-6|=4,\ |9-6|=3,\ |9-6|=3,\ |3-6|=3,\ |6-6|=0,\ |9-6|=3,\ |4-6|=2 \]
Step 3: Sum deviations.
\[ 4+3+3+3+0+3+2 = 18 \]
Step 4: Divide by total observations.
\[ \frac{18}{7} \approx 2.57 \]
Step 5: Final result.
\[ 2.57 \]
Step 1: Find mean.
\[ \bar{x} = \frac{2+9+9+3+6+9+4}{7} = \frac{42}{7} = 6 \]
Step 2: Compute deviations.
\[ |2-6|=4,\ |9-6|=3,\ |9-6|=3,\ |3-6|=3,\ |6-6|=0,\ |9-6|=3,\ |4-6|=2 \]
Step 3: Sum deviations.
\[ 4+3+3+3+0+3+2 = 18 \]
Step 4: Divide by total observations.
\[ \frac{18}{7} \approx 2.57 \]
Step 5: Final result.
\[ 2.57 \]
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