Question:

The maximum value of z=3x+2y subject to x+2y\ge2, x+2y\le8, x,y\ge0 is

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In linear programming, extrema occur at the corner points of the feasible region.
Updated On: Mar 19, 2026
  • 32
  • 24
  • 40
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: The feasible region is bounded by: x+2y=2, x+2y=8, x=0, y=0 Step 2: Corner points of feasible region: (2,0),(8,0),(0,1),(0,4) Step 3: Evaluate z=3x+2y: z(2,0)=6, z(8,0)=24, z(0,1)=2, z(0,4)=8 Step 4: Maximum value is 24 at (8,0).
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