Question:

The maximum value of $y = x(\log x)^2$ is:

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Always verify maxima using second derivative test.
Updated On: Jun 10, 2026
  • $e^{-2}$
  • $2e^{-2}$
  • $4e^{-2}$
  • $5e^{-2}$
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The Correct Option is C

Solution and Explanation

\[ y' = 2\log x + (\log x)^2 \] \[ \log x(2+\log x)=0 \] \[ x=1,\ e^{-2} \] Maximum at $x=e^{-2}$: \[ y = 4e^{-2} \]
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