Step 1: Understanding the Question:
The question asks for the mathematical condition required to achieve maximum power transfer in an AC network when both the source impedance and the load impedance are complex quantities.
Step 2: Key Formula or Approach:
Let the source impedance be represented as:
\[ Z_S = R_S + jX_S \]
And the load impedance be represented as:
\[ Z_L = R_L + jX_L \]
To maximize the active power transferred to the load, the load impedance must be the complex conjugate of the internal source impedance:
\[ Z_L = Z_S^* = R_S - jX_S \]
Step 3: Detailed Explanation:
• The average power delivered to the load in an AC circuit is given by:
\[ P = I^2 R_L \]
• The current \(I\) in the loop is:
\[ I = \frac{V_S}{|Z_S + Z_L|} = \frac{V_S}{\sqrt{(R_S + R_L)^2 + (X_S + X_L)^2}} \]
• Substituting the current into the power formula:
\[ P = \frac{V_S^2 R_L}{(R_S + R_L)^2 + (X_S + X_L)^2} \]
• To maximize \(P\) with respect to the load reactance \(X_L\), we choose \(X_L\) such that it cancels the source reactance \(X_S\):
\[ X_S + X_L = 0 \implies X_L = -X_S \]
• With the reactances canceled, the expression for power simplifies to:
\[ P = \frac{V_S^2 R_L}{(R_S + R_L)^2} \]
• Differentiating this power with respect to \(R_L\) and setting the derivative to zero yields the standard resistive matching condition:
\[ R_L = R_S \]
• Combining both conditions (\(R_L = R_S\) and \(X_L = -X_S\)), we get:
\[ Z_L = R_S - jX_S = Z_S^* \]
• This means the load impedance must be equal to the complex conjugate of the source impedance.
Step 4: Final Answer:
Maximum power transfer in an AC network occurs when \(Z_L = Z_S^*\).