Question:

The maximum potential energy of a block executing S.H.M. is E and amplitude of oscillation is 'A'. The kinetic energy of the block at amplitude A/2 is

Show Hint

Total energy is E; subtract the potential energy at A/2.
Updated On: Oct 1, 2026
  • \(\frac{3\text{E}}{4}\)
  • \(\text{E}\)
  • \(\frac{2\text{E}}{4}\)
  • \(\frac{5\text{E}}{4}\)
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Step 1: Total energy
The maximum potential energy equals the total energy: \(E = \frac12kA^2\).

Step 2: PE at A/2
\(U = \frac12k\left(\frac A2\right)^2 = \frac E4\).

Step 3: KE
\(K = E - \frac E4 = \frac{3E}{4}\). Option (A).

Final Answer:
The kinetic energy is 3E/4. \[ \boxed{\text{(A)}\ \frac{3E}{4}} \]
Was this answer helpful?
0
0