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the maximum potential energy of a block executing
Question:
The maximum potential energy of a block executing S.H.M. is E and amplitude of oscillation is 'A'. The kinetic energy of the block at amplitude A/2 is
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Total energy is E; subtract the potential energy at A/2.
MHT CET - 2026
MHT CET
Updated On:
Oct 1, 2026
\(\frac{3\text{E}}{4}\)
\(\text{E}\)
\(\frac{2\text{E}}{4}\)
\(\frac{5\text{E}}{4}\)
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The Correct Option is
A
Solution and Explanation
Step 1: Total energy
The maximum potential energy equals the total energy: \(E = \frac12kA^2\).
Step 2: PE at A/2
\(U = \frac12k\left(\frac A2\right)^2 = \frac E4\).
Step 3: KE
\(K = E - \frac E4 = \frac{3E}{4}\). Option (A).
Final Answer:
The kinetic energy is 3E/4. \[ \boxed{\text{(A)}\ \frac{3E}{4}} \]
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