Question:
The mass of Al deposited when 2 ampere current is passed through a solution of $Al_2(SO_4)_3$ for 1 hour is (F = 96500 C)
The mass of Al deposited when 2 ampere current is passed through a solution of $Al_2(SO_4)_3$ for 1 hour is (F = 96500 C)
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1 Faraday deposits 1 equivalent weight of a substance.
Updated On: Apr 27, 2026
- 0.67 g
- 1.34 g
- 0.134 g
- 0.355 g
- 0.067 g
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Faraday's First Law: $W = \frac{E \cdot I \cdot t}{96500}$.
Step 2: Meaning
Equivalent weight of Al ($E$) = $27/3 = 9$. Time ($t$) = $3600$ s.
Step 3: Analysis
$W = \frac{9 \times 2 \times 3600}{96500} = \frac{64800}{96500} \approx 0.671 \text{ g}$.
Step 4: Conclusion
Hence, correct answer is 0.67 g.
Final Answer: (A)
Faraday's First Law: $W = \frac{E \cdot I \cdot t}{96500}$.
Step 2: Meaning
Equivalent weight of Al ($E$) = $27/3 = 9$. Time ($t$) = $3600$ s.
Step 3: Analysis
$W = \frac{9 \times 2 \times 3600}{96500} = \frac{64800}{96500} \approx 0.671 \text{ g}$.
Step 4: Conclusion
Hence, correct answer is 0.67 g.
Final Answer: (A)
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