Question:

The mass of \( ^{15}\text{N} \) is 15.00011 amu and that of \( ^{16}\text{O} \) is 15.99492 amu. The mass of a proton is 1.00783 amu. Determine the binding energy of the last proton of \( ^{16}\text{O} \).

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Binding energy is obtained directly from mass defect.
Updated On: Mar 23, 2026
  • \(2.13\,\text{MeV}\)
  • \(0.13\,\text{MeV}\)
  • \(10\,\text{MeV}\)
  • 12.13MeV
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The Correct Option is A

Solution and Explanation


Step 1:
Mass defect: Δ m = m(¹5N) + mp - m(¹6O)
Step 2:
Δ m = 15.00011 + 1.00783 - 15.99492 = 0.01302amu
Step 3:
Binding energy: E = Δ m × 931 ≈ 2.13MeV
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