The major product ‘P’ for the following sequence of reactions is :
When solving reaction sequences:
Analyze each reagent step-by-step and apply known reaction mechanisms.
Clemmensen reduction (Zn/Hg, HCl) is used to reduce carbonyl groups to methylene (\(-\text{CH}_2-\)).
LiAlH\(_4\) reduces amides to amines.





1. First Step: Clemmensen Reduction (Zn/Hg, HCl):
The Clemmensen reduction converts the ketone group (\(-\text{C}= \text{O}\)) into a methylene (\(-\text{CH}_2-\)) group.
Starting compound:
\[\text{Ph-CH}_2-\text{CO-CH}_2-\text{CH}_2-\text{NH}_2.\]
After Clemmensen reduction:
\[\text{Ph-CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{NH}_2.\]
2. Second Step: LiAlH\(_4\) Reduction:
LiAlH\(_4\) reduces amides (\(-\text{CONH}_2\)) to amines (\(-\text{CH}_2-\text{NH}_2\)). In this compound, no further reduction occurs as the ketone has already been reduced to \(-\text{CH}_2-\) in the first step.
3. Final Product:
The major product (P) is:
\[\text{Ph-CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{NH}_2.\]
Final Answer: \(\text{Ph-CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{NH}_2\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are



What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)