
The reaction shown is an ozonolysis of 2-butene. The ozone (O3) cleaves the double bond, and the reduction with Zn/H2O results in the formation of aldehydes or ketones. For 2-butene, the ozonolysis reaction can be depicted as:
Reactant: \[\text{CH}_{3}\text{CH}=\text{CH}\text{CH}_{3}\]
Step 1: Ozonolysis cleaves the C=C bond.
Step 2: The products are two molecules of acetaldehyde (\[\text{CH}_{3}\text{CHO}\]).
Product (P): Each acetaldehyde molecule contains one oxygen atom.
| Molecule | Oxygen Atoms |
|---|---|
| Acetaldehyde (\[\text{CH}_{3}\text{CHO}\]) | 1 |
Since 2-butene is symmetrical, only one type of product is formed, which is acetaldehyde. The total number of oxygen atoms per molecule of product (P) is therefore 1.
Upon ozonolysis, the compound CH3–CH=CH–CH3 is cleaved at the double bond, resulting in two molecules of CH3–C=O.
Each resulting molecule contains one oxygen atom.
Hence, the total number of oxygen atoms present per molecule of the product is: 1
So, the correct answer is: 1.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,